Is log2 rational ? Justify
your
answer ?
Answers
Answered by
1
Answer:
No it is not..............................
Answered by
3
Answer:
Log2 is irrational.
Step-by-step explanation:
Assume that log 2 is rational, that is,
log2 = p/q ......(1)
where p, q are integers.
Since log 1 = 0 and log 10 = 1, 0 < log 2 < 1 and therefore p < q.
From (1),
2= 10^(p/q)
2^q=(2×5)^p
2(p-q)=5^p
where q – p is an integer greater than 0.
Now, it can be seen that the L.H.S. is even and the R.H.S. is odd.
Hence there is contradiction and log 2 is irrational.
Hope it helps you!!
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