is my questions too hard ......no one try
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Initial Velocity = 20m/s
height of tower =25m
(A.)→ using third equation of motion
.
It will reach 20 m of height above the tower and 45 m above the ground
(B.)→ Using second equation of motion
let 't' be time taken then
.
height of tower =25m
(A.)→ using third equation of motion
.
It will reach 20 m of height above the tower and 45 m above the ground
(B.)→ Using second equation of motion
let 't' be time taken then
.
snehal1800:
thats gr8.....thank you
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