is question paper ka 2nd question solve kar do
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dinesh94:
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HCF of 96 and 404 by prime factorisationmethod:- Since, 96 = 2 × 2 × 2 × 2 × 2 × 3 and, 404 = 2 × 2 × 101. So, HCF of 96 and 404 = Product of common prime factors = 2 × 2 = 4.
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96=2*2*2*2*2*3
404=2*2*101
HCF = 2*2=4
404=2*2*101
HCF = 2*2=4
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