Question

is question paper ka ix part solve kardo

Answer 1

discriminant=
${( - 1)}^{2} - 4(6)( - 2) \\ 1 + 48 = 49$

Answer 2

${6x}^{2} - x - 2 = 0$
$d = {b}^{2} - 4ac$
${1}^{2} - 4(6)( - 2)$
$1 + 48$
$49$