Question

is series √3,√6,√9,√12 .............an AP? give reason

Answer 1

$\sqrt{3} \sqrt{6} \sqrt{9} \sqrt{12}$
$\sqrt{6} - \sqrt{3}$
is not equal to
$\sqrt{9} - \sqrt{6}$

it is not an AP bcoz the difference between its consecutive terms r not equal .

hope it helps uh ....
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