Question

is sin P= then find tan theta cos theta values​

Answer 1

Answer:

We have sec

2

θ−tan

2

θ=1

(secθ−tanθ)(secθ+tanθ)=1

(secθ−tanθ)p=1 (∵secθ+tanθ=p)

(secθ−tanθ)=

p

1

secθ+tanθ=p

secθ−tanθ=

p

1

2secθ=

p

p

2

+1

secθ=

2p

p

2

+1

cosθ=

p

2

+1

2p

sinθ=

1−cos

2

θ

cos

2

θ=(

p

2

+1

2p

)

2

cos

2

θ=

p

4

+1+2p

2

4p

2

1−cos

2

θ=1−

p

4

+1+2p

2

4p

2

=

(p

2

+1)

2

p

4

+1+2p

2

−4p

2

=

(p

2

+1)

2

p

4

+1−2p

2

=

(p

2

+1)

2

(p

2

−1)

2

1−cos

2

θ

=

p

2

+1

p

2

−1

∴sinθ=

p

2

+1

p

2

−1

∴cosec θ=

sinθ

1

=

p

2

−1

p

2

+1

Step-by-step explanation:

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