is the attached problem correct?
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Answered by
1
Answer:
no it's wrong it's an factorisation question their is formula
hope this helps you
Answered by
2
Answer:
No....
correct answer =>x² + y² + 2xy - z²
Step-by-step explanation:
(x+y+z) (x+y-z)
let (x+y) = a
=> (x+y+z) (x+y-z)= (a + z ) ( a-z)
using identity (m²-n²) = (m+n)(m-n)
= ( a² - z²)
putting value of a
we get
=> (x+y)² - z²
= (x² + y² + 2xy ) - z²
= x² + y² + 2xy - z²
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