Math, asked by Megarox, 1 year ago

Is the decimal form 129/2^5x5^7x7^5 a terminating or non terminating . give a brief explanation.​

Answers

Answered by AashimaSharma123
54

IT IS NON TERMINATING

BECAUSE IN DENOMINATOR THERE MUST BE 2^m×5^n AS A FACTOR

THERE FOR IT IS A NON TERMINATING DECIMAL EXPANSION

PLZ MARK IT A BRAINLIEST


Megarox: how to make it terminating
AashimaSharma123: we can't make it TERMINATING
Megarox: okay
Answered by pinquancaro
71

The decimal form \dfrac{129}{2^5\times 5^7\times 7^5} is non terminating.

Step-by-step explanation:

To find : Is the decimal form \dfrac{129}{2^5\times 5^7\times 7^5} a terminating or non terminating ?

Solution :

The number to be terminate when the denominator is in the form 2^n\times 5^n

Number \dfrac{129}{2^5\times 5^7\times 7^5}

Denominator of number has 7 in denominator.

So denominator is not in form of 2^n\times 5^n

Therefore, the decimal form \dfrac{129}{2^5\times 5^7\times 7^5} is non terminating.

#Learn more

Has the rational number 441/2²5^7x7² a terminating or non terminating decimal number? why​

https://brainly.in/question/9854108

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