the population of a town increases 10%every 3years. if the present population of the town is 72600,calculate : 1) its population after 6 years ; 2) its population 6 years ago.
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The population of a town increases by 10% every 3 years. If the present population of the town is 72,600, calculate:
(i) its population after 6 years
(ii) its population 6 years ago
Asked by Topperlearning User1st August 2017, 9:48 AM
Answered by Expert
Answer:
(i) Present population of town = 72,600
Population increases by 10% every 3 years
Population after 3 years= 72,600 + 10% of 72,600
= 72,600 + 7,260
= 79,860
Population after 6 years =79,860 + 10% of 79,860
= 79,860 + 7,986
=87,846
(ii) Let population 6 years ago = 100
Then population 3 years ago = 100 + 10% of 100
= 100 + 10
= 110
And present population = 110 + 10% of 110
= 110 + 11
= 121
When present population is 121, population 6 years ago= 100
When present population is 72,600, population 6 years ago
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