Question

Is the functions Sinx uniformly continuous on (0,1)?​

Answer 1

Step-by-step explanation:

To show that x sin x is not uniformly continuous, we use the third criterion for nonuniform continuity. +yn sin yn)=4π2. In particular, there exists a K such that for n ≥ K, |xn sin(xn) − un sin(un)| > 1. So x sin x is not uniformly continuous