Question

is the lines given by 3x + 2ky equals 2 and 2x + 5 + 1 equal to 0
are parallel then find value of k

Answer 1

3 X + 2 ky = 2 and 2x + 5 + 1 = 0
3 X + 2 ky = 2 and 2x + 6 = 0
3 X + 2 ky= 2 and 2x = - 6
3 X + 2 ky = 2 and X = - 3

substitute X value in the equation 3 X + 2 k y = 2
3(-3)+ 2ky =2
-9+2ky=2
2ky=11
ky=11/2
KY = 5.5
y=5.5k





3 X + 2 k y = 2
3(-3)+2k(5.5k)=2
-9 + 11 k =2
11 k = 2+9
11 k =11
k=11/11
k=1