Question

is
The number of mole of atoms
Present in 0.2g of C3
H4 is 0.2g
the number of moles pf atoms
present in C3 H4​

Answer 1

Answer:

hi

Explanation:

ANSWER

Combustion of methane :

CH

4

+2O

2

⟶CO

2

+2H

2

O

Given weight of methane =16g

Molecular weight of methane =16g

No. of moles of methane in 16g of it =

mol. wt.

given wt.

=

16

16

=1 mole

From the reaction,

Amount of water produced by the combustion of 1 mole of methane = 2 moles

weight of 1 mole of water =18g

⇒ weight of 2 moles of water =2×18=36g

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.

pls mark my answer has brilliant