Question

Is the probability of winning a game is 0.07 what is the probability of losing it

Answer 1

answer:

Probability of losing the game = 9.93

Step-by-step explanation:

HELLO DEAR,

GIVEN : Probability of winning a

game = 0.07

To find the probability of losing a game.

SOLUTION: Probability of

winning the game P(E)= 0.07

{By using formula of P(E) + P(E)'= 1}

And probability of losing the game P(E)'= 1- P(E)

P(E)'= 1- 0.07

P(E)'= 0.93

I HOPE IT'S HELP YOU DEAR,

THANKS.

Answer 2

SOLUTION

GIVEN

The probability of winning a game is 0.07

TO DETERMINE

The probability of losing the game

CONCEPT TO BE IMPLEMENTED

In any random experiment if the total number of elementary ( simple) events in the sample space be n ( a finite number) among which the number of elementary events favourable to an event E , connected with the experiment be m then the probability of the event E is denoted by P (E) and defined as

$\displaystyle \sf{}P(E) = \frac{m}{n}$

Now the total number of possible outcomes = n and the total number of possible outcomes for the event E is m

Let E' be the event not E

Then the total number of possible outcomes for the event E' = n - m

Then the probability of the event E'

= P(E')

$\displaystyle \sf{ = \frac{n - m}{n} }$

$\displaystyle \sf{ = 1 - \frac{ m}{n} }$

= 1 - P(E)

EVALUATION

Let E be the event of winning a game

∴ P(E) = 0.07

Then E' = The event of loosing the game

Hence the required probability

= P(E')

= 1 - 0.07

= 0.93

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Additional Information :-

For an impossible event, the number of favourable cases is zero and hence it's probability is 0

On the other hand for a certain event S all cases are favourable cases and hence it's probability is 1

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