Is the tangent at (1,7) to the curre x²=y-6 touches
the circle x2+y2+16x+12y+c=0 , then the value of. C is
(a) 95
(6) l95 (C) 185 (d) 85
Answers
EXPLANATION.
Tangent at (1,7) to the curve x² = y - 6.
Touches the circle x² + y² + 16x + 12y + c = 0.
A we know that,
General equation of circle.
⇒ x² + y² + 2gx + 2fy + c = 0.
Centre of circle = (-g,-f).
Centre of circle = (-8,-6).
Radius of circle = √g² + f² - c.
Radius of circle = √(-8)² + (-6)² - c.
Radius of circle = √64 + 36 - c.
Now, we need to find slope of the equation, we get.
⇒ x² = y - 6.
Differentiate w.r.t x, we get.
⇒ 2x = dy/dx - 0..
⇒ 2x = dy/dx.
Put the value of x = 1 in the equation, we get.
⇒ 2(1) = dy/dx.
⇒ dy/dx = 2.
dy/dx = slope of tangent.
As we know that,
Equation of tangent.
⇒ (y - y₁) = m(x - x₁).
⇒ (y - 7) = 2(x - 1).
⇒ y - 7 = 2x - 2.
⇒ 2x - 2 - y + 7 = 0.
⇒ 2x - y + 5 = 0.
As we know that,
Length of perpendicular.
From (x₁, y₁) to a straight line ax + by + c = 0 then,
⇒ P = |ax₁ + by₁ + c/√a² + b²|.
Perpendicular = Radius.
⇒ |2x - y + 5/√(2)² + (1)²| = √64 + 36 - c.
⇒ |2(-8) - (-6) + 5/√4 + 1 | = √100 - c.
⇒ | - 16 + 6 + 5/√5 | = √100 - c.
⇒ | - 5/√5| = √100 - c.
⇒ √5 = √100 - c.
⇒ 5 = 100 - c.
⇒ 5 - 100 = - c.
⇒ - 95 = - c.
⇒ c = 95.
Option [A] is correct answer.
Step-by-step explanation:
Given equation of curve is
Slope of tangent is m
Equation of tangent at the point(1,7) is given by
Given equation of circle is
If the tangent touches the circle , then distance from the centre =radius
= Distance of (-8,-6) from 2x-y-5=0 is the radius