Is there a finite number of prime numbers?
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★ THEORY OF NUMBERS ★
Utilizing mathematical generality at it's best :
If possible , suppose that the numbers of prime is finite
∃ the greatest prime say q
Let b denote the product of these primes , 2 , 3 , 5... q
i.e., let
b = 2 × 3 × 5 × ... q ... (i)
let , a = b + 1 ... ( ii )
Surely , a ≠ 1
aslike : a = b + 1 > 1
The Number " a " must have a prime say factor p
i.e. , p | a
Now , p is one of the primes 2 , 3 , 5 , 7 , ... q
Accordingly to our assumptions , it's the only primes series , that's why putting up in consideration
b = 2 ( 3 ) ( 5 ) ... q
p | b
Again , p | a and p | b
p | a - b OR p | 1
From eqn ( ii ) ... a - b = 1
p = 1 [ which is impossible ]
Because , 1 is not a prime number
So , our supposition is false ,
HENCE ,
THE NUMBER OF PRIMES IS INFINITE
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Utilizing mathematical generality at it's best :
If possible , suppose that the numbers of prime is finite
∃ the greatest prime say q
Let b denote the product of these primes , 2 , 3 , 5... q
i.e., let
b = 2 × 3 × 5 × ... q ... (i)
let , a = b + 1 ... ( ii )
Surely , a ≠ 1
aslike : a = b + 1 > 1
The Number " a " must have a prime say factor p
i.e. , p | a
Now , p is one of the primes 2 , 3 , 5 , 7 , ... q
Accordingly to our assumptions , it's the only primes series , that's why putting up in consideration
b = 2 ( 3 ) ( 5 ) ... q
p | b
Again , p | a and p | b
p | a - b OR p | 1
From eqn ( ii ) ... a - b = 1
p = 1 [ which is impossible ]
Because , 1 is not a prime number
So , our supposition is false ,
HENCE ,
THE NUMBER OF PRIMES IS INFINITE
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
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