is there any brainliest person who can Answer my question
Attachments:
Answers
Answered by
1
=tanxtanxtanx
log y = tanxtanxlogtanx
Before differentiating :
z=tanxtanx
log z = tanx log tanx
Differentiating both the sides w.r.t. x
1z dzdx = sec2x log tanx+tanx. 1tanx. sec2x
dzdx = tanx log tanx (sec2x log tanx + sec2x)Going back to the question
log y = z log tan x
Differentiating both the sides w.r.t. x
1y dydx = z′ log tanx + z 1tanx sec2x
dydx = tanxtanxtanx (tan x log tan x(sec2 x log tan x+ sec2 x)log tan x + tan xtan x sec2 xtan xPutting the value of x as π4
11 × (1×0(12×0+12)×0+1×0×121)
=1(0+0)
=0
Anonymous:
what bro....
log10(∞) = ?
Since infinity is not a number, we should use limits:
x approaches infinity
The limit of the logarithm of x when x approaches infinity is infinity:
lim log10(x) = ∞
x→∞
x approaches minus infinity
The opposite case, the logarithm of minus infinity (-∞) is undefined for real numbers, since the logarithmic function is undefined for negative numbers:
lim log10(x) is undefined
Since infinity is not a number, we should use limits:
x approaches infinity
The limit of the logarithm of x when x approaches infinity is infinity:
lim log10(x) = ∞
x→∞
x approaches minus infinity
The opposite case, the logarithm of minus infinity (-∞) is undefined for real numbers, since the logarithmic function is undefined for negative numbers:
lim log10(x) is undefined
is it clear brother..........
Answered by
0
pls mark as brainliest
Attachments:
Similar questions