Question

(x-3)^2-7(x-3)+10 factorise

Answer 1

Let x-3=a  a^2-7a+10=0 a^2-5a-2a+10=0 a(a-5)-2(a-5)=0 (a-5)(a-2)=0  Either a=2 or a=5  x-3=2 x=5  x-3=5 x=8 x=5 or x=8...*Ans*