Question

Is there any number that will divide 20 and 135 leaving remainders 3 and 4 respectively?

Answer 1

Answer:

NIL

Step-by-step explanation:

N = 20x + 3 = 135y + 4

20x + 3 = 135y + 4

20x = 135y + 1 --------(1)

As you can see for any value of y, you will not get a natural number value for x which satisfies (1). So, no such numbers exist