Is there any real value of p for eqn x2 +2x+ (p2-1)=0
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Answer:
yes as i think it is possible
Step-by-step explanation:
compromising the question x2 +2x+ (p2-1)=0 to ax^2+bx+c
then we obtain that
a=1 ...........(1)
b=2 ............(2)
c=p2-1 .............(3)
for real value
D<0
by the quadratic formula
D= b^2-4(a)(c)
substituting the value of (1)(2)&(3)
D= (2)^2-4(1)(p2-1 )
where D<0
so
4-4(p2-1)<0
4-4p2+4<0
8-4p2<0
4p2<8
p2<8/2
p2<4
p<root under 4/2
p<2
and as i think it can be possible if u satisfied pls mark it brainly
hope it helps to u
rakhithakur:
MArk it's brainly
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