Question

is there anyone on brainly smart enough to solve this?​

Answer 1

Answer:

Let θ be the angle the other end and the vertical from center subtends at the center.

Let λ be the mass per unit length of the chain=lm.

Gravitational potential energy of the chain=∫0θλRdθg(Rcosθ)

=lmR2gsinθ

Since R>l, θ=Rl

⟹GPE=lmR2gsinRl

Answer 2

Answer:

$\huge{ \mathcal{ \purple{♡A} \green{n} \pink{s} \blue{w} \purple{e} \green{r} \pink{}}}$

Tq fr ur answer mate...

I hav done my best hope this is correct, n plzz mention if it's wrong....

$refr \: the \: pic \: attached...$

${ \red{ \fbox{ \green{ \blue{ \underline{ \mathcal \purple{hope \: this \: helps \: u}}}}}}}$

☺✌

c that step...hope u got...