Question

is there is a positive error of 20% in the measurement of velocity of a body then the error in the measurement of kinetic energy is

Answer 1

Kinetic energy = 0.5mv²

Let mass be m and velocity be V for the actual measurements

For the measurements with error V will be :

1.20V

The new kinetic energy with error will be :

Kinetic energy = 0.5m × 1.20²V²

= 0.72mV²

The error in measuring kinetic energy is thus :

0.72mV² - 0.5mV² = 0.22mV²

(0.22 / 0.5) × 100 = 44%