Question

Is this equation is quadratic equation : (x+1) (x+2) =1​

Answer 1

$(x + 1)(x + 2) = 1 \\ x(x + 2) + 1(x + 2) = 1 \\ {x}^{2} + 2x + x + 2 = 1 \\ {x}^{2} + 3x + 2 - 1 = 0 \\ {x}^{2} + 3x + 1= 0$

Yes, it's a quadratic equation

Answer 2

Answer:

yes, This is a quadratic equation.

Step-by-step explanation:

x(x+2) +1(x+2) = 1

x

${x}^{2} + 2x + x + 2 = 1$

x

${x}^{2} + 3x = 1 - 2$

$x { }^{2} + 3x + 1 = 0$