Physics, asked by Dahiya22, 1 year ago

Is u+a/2(2n-1) is dimensionally correct or not??
Please answer
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Answers

Answered by Anonymous
9
u+a/2(2n-1) is dimensionally correct.

Dahiya22: Please give the solution
Anonymous: So, S(nth) = distance travelled in nth second

i.e S(nth) = [L]/[T] = [LT^-1] dimensionally

RHS

Now, U+(1/2)*a*(2n-1) = where,

U= initial velocity = [LT^-1]

a= acceleration = [LT^-2]

2n-1= n=time = [T]

1/2=dimensionless = [M°L°T°]

——————————————————

U+(1/2)*a*(2n-1)= [LT^-1]+[LT^-2]*[T]

[LT^-1]+[LT-^1]=[LT^-1] by principle of homogeneity.

As LHS= RHS dimensionally i.e [LT^-1]

Therefore, it is dimensionally correct.
Dahiya22: Thanks
Anonymous: wlcm
Answered by soniatiwari214
0

Concept:

  • Dimensional analysis
  • One dimensional motion

Given:

  • Distance travelled in the nth second Sn = u+a/2(2n-1)

Find:

  • Whether Sn = u+a/2(2n-1) is dimensionally correct

Solution:

Consider the right-hand side

  • Distance covered in the nth second Sn = [LT⁻¹]

Consider the left-hand side

  • u is the initial velocity, so u =[LT⁻¹]
  • a is the acceleration, so a = [LT⁻²]
  • n is the time, so n = [T]
  • u+a/2(2n-1) =   [LT⁻¹]

This is equal to the right-hand side.

Therefore, the equation is dimensionally correct.

#SPJ2

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