Question

is (x-2)^2 +1 =2x-3 a quadratic
equation ? If yes find the roots.
*​

Answer 1

Step-by-step explanation:

(x-2)*2+1=2x-3

x*2+4-4x+1 =2x-3

x*2 +5 -4x -2x +3 = 0

x*2-2x -4x+8=0

x(x-2)-4(x-2)=0

(x-4)(x-2)=0

therefore ,x=4,2

Answer 2

Answer:

Yes, it is a quadratic equation

And the roots are x=2 or x=4

Step-by-step explanation:

(x-2)^2 +1 = 2x-3

》{x^2 + (2)^2 -2.x.2} + 1 = 2x -3

》(x^2 + 4 - 4x ) + 1 = 2x- 3

》x^2 - 4x - 2x + 4 + 1 +3 = 0

》x^2 - 6x + 8 = 0

therefore , the degree of the equation is 2

Hence, it is a quadratic equation

Now, by middle term factorization we get

x^2 - 4x - 2x + 8 = 0

》x(x - 4) - 2(x - 4) = 0

》(x - 2) - ( x - 4) = 0

》( x - 2) = 0 or ( x - 4) = 0

》x = 2 or x = 4

Hence 2 and 4 are the roots of the quadratic equation

Hope you understand the solution properly

plssss subscribe to me and like my solution