Question

is (x-7) a factor of (x^2-5x+24)​

Answer 1

Answer:

Step-by-step explanation:

P(x) = (x^2-5x+24)

G(x) =( x-7)To determine the zero of g(x)

g(x) = 0

x-7= 0

x= 7

By remainder theroem

Remainder = p (7)

= 7^2-5×7+24

= 49-35+24

= 38

Since the remainder us not zero , hence g(x) is not a factor of p(x)