Question

Is (y - 1 ) the factor of f(y) = y3 - 6y2 + 6y + 1

Answer 1

Answer:

No

Step-by-step explanation:

y-1=0

y=1

Now,

f(y)= y³-6y²+6y+1

f(1)= (1)³-6(1)²+6(1)+1

f(1)= 1-6+6+1

-6 and +6 will be cancelled

f(1)= 2

So, y-1 is not the factor of y-1