Question

Is y = 3^(1/3) + 3<br />then y^3 - 9y^2+27y​

Answer 1

The final value: $3^{1}- (3)^{(\frac{8}{3})}}+(3)^{(\frac{10}{3})}$

Step-by-step explanation:

$\ Given \ value:\\\\\ y= 3^{(\frac{1}{3})}\\\\\ Find:\\\\y^3-9y^2+27y\\\\\ Solution:\\\\(3^{(\frac{1}{3})})^3- 9(3^{(\frac{1}{3})})^2+27(3^{(\frac{1}{3})}) \\\\\rightarrow (3^{1}- 9(3^{(\frac{2}{3})}+27(3^{(\frac{1}{3})}) \\\\\rightarrow (3^{1}- (3)^2(3^{(\frac{2}{3})}+(3)^3(3^{(\frac{1}{3})}) \\\\\rightarrow (3^{1}- (3)^{(\frac{8}{3})}}+(3)^{(\frac{10}{3})})$

Learn more:

• Simplify: https://brainly.in/question/4393667