इस प्रश्न का उत्तर दिया जैय
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first year saving
a = p(1+r)^n
a= 200 ( 1+ 5/100) ^ 3
a= 200(21/20)
a= 200 * (9261 / 8000)
a = 9261/40
a = 231.525.
second year saving
a = p(1+r)^n
a= 200 (1+ 5/100) ^ 3
a= 200(21/20)^2
a= 200*441/400
a= 441/2 = 220.5
third year earning
a =p(1+r)^n
a= 200(1+ 5/100)^1
a= 200 * 21 /20
a= 10*21 = 210.
sum of all three amounts = 231.525+220.5+210 = 662.025= 662.02
therefore answer = ₹662.02
a = p(1+r)^n
a= 200 ( 1+ 5/100) ^ 3
a= 200(21/20)
a= 200 * (9261 / 8000)
a = 9261/40
a = 231.525.
second year saving
a = p(1+r)^n
a= 200 (1+ 5/100) ^ 3
a= 200(21/20)^2
a= 200*441/400
a= 441/2 = 220.5
third year earning
a =p(1+r)^n
a= 200(1+ 5/100)^1
a= 200 * 21 /20
a= 10*21 = 210.
sum of all three amounts = 231.525+220.5+210 = 662.025= 662.02
therefore answer = ₹662.02
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