Isha walks 9 m east and then 12 m north.How far is she away from her initial position.
Answers
Answered by
5
distance travelled is 21 m
displace ment is 15 m from initial position
displace ment is 15 m from initial position
Answered by
13
By Pythagoras Theorem,
side^2 + side^2 = hypotenuse^2
9^2 +12^2 = hypotenuse^2
81 + 144 = hypotenuse^2
225 = hypotenuse^2
√225 = hypotenuse
25 = hypotenuse
Now,
We can say that she is 15m away from her initial position
i hope this will help you
-by ABHAY
side^2 + side^2 = hypotenuse^2
9^2 +12^2 = hypotenuse^2
81 + 144 = hypotenuse^2
225 = hypotenuse^2
√225 = hypotenuse
25 = hypotenuse
Now,
We can say that she is 15m away from her initial position
i hope this will help you
-by ABHAY
Similar questions