Question

iske chapter ka name​

Answer 1

Explanation:

$\huge{\green{\underline{\underline{\tt{Solution:}}}}}$

Given,

☞ x = -1

Let, P(x) = 5x-4x²+3

$→\;{\sf{P(-1) = 5(-1)-4(-1)²+3}}$

$→\;{\sf{P(-1) = -5-4(+1)+3}}$

$→\;{\sf{P(-1) = -5-4+3}}$

$→\;{\sf{P(-1) = -9+3}}$

$➝\;\red{\bf{P(-1) = -6}}$

Hope It Helps You ✌️

$\huge\underbrace{\green{\tt{\diamond\; Solution:}}}$

Let

Total Pocket Money be 'x'

Now, Savings = 30% of x

$→\;\Large{\frac{30}{100}×x}$

☞ $→\;\Large{\frac{30x}{100}}$

Given,

Amount Spend = Rs. 280.

$→\;\Large{\sf{x - \frac{30x}{100} = 280}}$$\huge{\green{\underline{\underline{\tt{Solution:}}}}}$

Given,

☞ x = -1

Let, P(x) = 5x-4x²+3

$→\;{\sf{P(-1) = 5(-1)-4(-1)²+3}}$

$→\;{\sf{P(-1) = -5-4(+1)+3}}$

$→\;{\sf{P(-1) = -5-4+3}}$

$→\;{\sf{P(-1) = -9+3}}$

$➝\;\red{\bf{P(-1) = -6}}$

Hope It Helps You ✌️

$\huge\underbrace{\green{\tt{\diamond\; Solution:}}}$

Let

Total Pocket Money be 'x'

Now, Savings = 30% of x

$→\;\Large{\frac{30}{100}×x}$

☞ $→\;\Large{\frac{30x}{100}}$

Given,

Amount Spend = Rs. 280.

$→\;\Large{\sf{x - \frac{30x}{100} = 280}}$