Question

it, т = 92 , = 60°, К свет.
26 х н ( по - Sino x Coss 0
S60​


please give the answer

Answer 1

Answer:

$6 {r}^{2} ( \frac{\pi \theta}{360} - {\sin( \theta) \over2} \times \frac{ \cos( \theta) }{2} ) \\ \\ = 6 \times {28}^{2} ( \frac{\pi \times 60}{360} - \frac{ \sin(60) \cos(60) }{4} ) \\ \\ = 6 \times {28}^{2} ( \frac{\pi}{6} - \frac{ \sqrt{3} \times 1 }{16} ) \\ \\ = 6 \times {28}^{2} ( \frac{22}{7 \times 6} - \frac{ \sqrt{3} }{16} ) \\ \\ = 6 \times {28}^{2} ( \frac{22 \times 16 - 21 \sqrt{3} }{21 \times 16} ) \\ \\ = 14(352 - 21 \times 1.73) \\ \\ \approx4418.78 \: {cm}^{2}$