Question

It a, b, c are prime numbers, then
lcm a5b²c, a 3, 64, c2
=​

Answer 1

Answer:

Using, A.M≥G.M

Using, A.M≥G.M6(a1+b2+c3)≥(a1b21c31)6=21

Using, A.M≥G.M6(a1+b2+c3)≥(a1b21c31)6=21⇒(a1+b2+c3)≥3

Using, A.M≥G.M6(a1+b2+c3)≥(a1b21c31)6=21⇒(a1+b2+c3)≥3Hence, option 'B' is correct.

Step-by-step explanation:

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