Math, asked by aaravchauha19, 11 months ago

it costs rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. if it is painted at the rate of rs 20 per sq m , find the inner curved surface area of the vessel and capacity of the vessel​

Answers

Answered by vienchiez
39

Answer:

Cost of painting=Rs 2200

=Rs 20 ×CSA=Rs 2200

=CSA=RS 2200/Rs20

=CSA =110m²

Now, CSA =110m²

=2πrh =110m²

=2(22/7)×r×10m=110m²

=r=(110m²×7)/2×22×10m

=r=1.75m

Capacity (Volume )of vessel:

=πr²h

=(22/7)×(1.75m)²×10m

=55m³

Answered by kelinjoy54
12

Answer: Cost of painting=Rs 2200

=Rs 20 ×CSA=Rs 2200

= inner curved surface area =RS 2200/Rs20

=CSA =110m²

Now, CSA =110m²

=2πrh =110m²

=2(22/7)×r×10m=110m²

=r=(110m²×7)/2×22×10m

=r=1.75m

the volume of the vessel:

=πr²h

=(22/7)×(1.75m)²×10m

=55m³

Similar questions