it costs rs 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. if it is painted at the rate of rs 20 per sq m , find the inner curved surface area of the vessel and capacity of the vessel
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Answered by
39
Answer:
Cost of painting=Rs 2200
=Rs 20 ×CSA=Rs 2200
=CSA=RS 2200/Rs20
=CSA =110m²
Now, CSA =110m²
=2πrh =110m²
=2(22/7)×r×10m=110m²
=r=(110m²×7)/2×22×10m
=r=1.75m
Capacity (Volume )of vessel:
=πr²h
=(22/7)×(1.75m)²×10m
=55m³
Answered by
12
Answer: Cost of painting=Rs 2200
=Rs 20 ×CSA=Rs 2200
= inner curved surface area =RS 2200/Rs20
=CSA =110m²
Now, CSA =110m²
=2πrh =110m²
=2(22/7)×r×10m=110m²
=r=(110m²×7)/2×22×10m
=r=1.75m
the volume of the vessel:
=πr²h
=(22/7)×(1.75m)²×10m
=55m³
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