Question

it f(x)=-root25-x² then find the value lt x tends 1 f(x)-f(1)/x-1​

Answer 1

Answer:

Consider

x→1

lim

x−1

f(x)−f(1)

We know that,

x→a

lim

x−a

f(x)−f(a)

=f

′

(a)

So, we get

x→1

lim

x−1

f(x)−f(1)

=

1

f

′

(1)

=

∣

∣

∣

∣

∣

∣

2

25−x

2

1(−2x)

∣

∣

∣

∣

∣

∣

at x=1

=−

24

1

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