Question

it girl it twice as old as her sister four years hence, the
product of their ages (in years) will be 160 find this present a
age​

Answer 1

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Answer 2

Solution:

Let the present age of her sister be x years.

Then, the girl's present age = 2x years.

Product of their ages 4 years hence = (x + 4)(2x + 4).

∴ (x + 4)(2x + 4) = 160

[tex][/tex]

→ 2x² + 12x -144 = 0

→ x² + 6x - 72 = 0

→ x² + 12x - 6x - 72 = 0

→ x(x + 12) - 6(x + 12) = 0

→ (x + 12)(x - 6) = 0

→ x + 12 = 0 or x - 6 = 0

→ x = -12 or x = 6

→ x = 6 (the present age cannot be negetive)

∴ Sister's present age = 6 years and girl's present age = 12 years.

________________________

Answer :

Present ages of:

• Girl = 12 years.
• Her sister = 6 years.