Math, asked by 8722979584, 1 year ago

it has been found that 80% of all tourists who visit india, visits delhi,70% of them visit mumbai and 60% of them visit both.what is a probability that a tourist will visit at least one city.also find the probability that he will visit neither of the two cities.

Answers

Answered by Geekydude121
11
Acc.to question,

The probability of tourists visiting Delhi = 80% = 80/100 = 4/5

The probability of tourists visiting Mumbai = 70% = 70/100 = 7/10

The probability of tourists visiting both Delhi & Mumbai = 60% = 60/100 = 3/5

The probability of tourists visiting at least one city = P(Delhi) + P(Mumbai) - P(Delhi intersection Mumbai) i.e. both cities

or, 4/5 + 7/10 - 3/5  =  9/10

The probability of tourists visiting neither the cities = 1 -  Probability of tourists visiting at least one city  =  1 - 9/10  =  1/10(Ans)  [Subtracting the tourists visiting either of the cities will give the list of tourists who visited none of the cities.]
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