it has been found that 80% of all tourists who visit india, visits delhi,70% of them visit mumbai and 60% of them visit both.what is a probability that a tourist will visit at least one city.also find the probability that he will visit neither of the two cities.
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The probability of tourists visiting Delhi = 80% = 80/100 = 4/5
The probability of tourists visiting Mumbai = 70% = 70/100 = 7/10
The probability of tourists visiting both Delhi & Mumbai = 60% = 60/100 = 3/5
The probability of tourists visiting at least one city = P(Delhi) + P(Mumbai) - P(Delhi intersection Mumbai) i.e. both cities
or, 4/5 + 7/10 - 3/5 = 9/10
The probability of tourists visiting neither the cities = 1 - Probability of tourists visiting at least one city = 1 - 9/10 = 1/10(Ans) [Subtracting the tourists visiting either of the cities will give the list of tourists who visited none of the cities.]
The probability of tourists visiting Delhi = 80% = 80/100 = 4/5
The probability of tourists visiting Mumbai = 70% = 70/100 = 7/10
The probability of tourists visiting both Delhi & Mumbai = 60% = 60/100 = 3/5
The probability of tourists visiting at least one city = P(Delhi) + P(Mumbai) - P(Delhi intersection Mumbai) i.e. both cities
or, 4/5 + 7/10 - 3/5 = 9/10
The probability of tourists visiting neither the cities = 1 - Probability of tourists visiting at least one city = 1 - 9/10 = 1/10(Ans) [Subtracting the tourists visiting either of the cities will give the list of tourists who visited none of the cities.]
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