Question

It is 260km from Patna to Ranchi by air and 320km by road. An aeroplane takes 30 minutes to go from Patna to Ranchi where as a deluxe bus takes 8 hours a} Fimd the average speed of the plane b) Find the average speed of bus c) Find the average velocity of plane and d) Find the average velocity of bus. Concept of Physics - 1 , HC VERMA , Chapter "Rest and Motion : Kinematics

Answer 1

Solution:

A) average speed of plane:
Distance from Patna to Ranchi =260km
Time taken =30min=30/60=0.5hrs
Average speed= Total distance/ Time
=260/0.5
=2600/5=520 km/hr

b) Average speed of bus:
Distance =320km
time=8hrs
Average speed = Total distance/ time
=320/8=40 km/hr

c) Average velocity of Plane :

Average velocity= Displacement/time
Displacement of plane =260 km[ ∵ it is straight path]
Displacement of plane=260/0.5=520 km/hr and direction is from Patna to Ranchi straight.

d) Average velocity of bus=260/8=32.5km/hr and direction is from Patna to Ranchi straight.

Answer 2

heya..........


 (a) Vavg of plane (Distance / Time) = 260/0.5 = 520 km/hr......30min=1/2=0.5

 (b) Vavg of bus = 320 / 8 = 40 km/hr.

(c)avg velocity of plane=260/.5=520km/hr

d) Straight path distance between plane to Ranchi is equal to the displacement of bus. ∴

Velocity = V ⃗ave = 260/8 = 32.5 km/hr.

tysm..#gozmit