Question

it is all in the photo ​

Answer 1

Explanation:

v= 36*5/18 = 10 m/s, t =10 sec

i) acceleration = (10-0)/10 = 1 m/s^2

ii) distance = (10^2)/(2*1) = 50 m

iii) distance travelled in 6th sec

=1/2*1*(6*2 -1)= 5.5 m

iv) velocity at the end of 6th sec

v^2= 0+ 2*1*18 = 36

taking square root on both sides

v =6m/sec

Answer 2

Answer:

(a) acceleration = 1 m/s^2

(b) distance = 50 m

(c) velocity at 6^th second = 7 m/s

(d) distance travelled in 6th second = 5.5 m