Math, asked by Sankitha, 10 months ago

It is claimed that a random sample of 49 tyres has a mean life of 15,200 kms. Is the sample drawn from a population whose mean is 15,150 kms and whose standard deviation is 1,200 kms? Test the significance at 0.05 level.

Answers

Answered by lambadeepak
9

Answer:

Step-by-step explanation:

Test the claim at 0.05 level significance. ... Level of significance : α = 0.05 4. ... Example 8 : It is claimed that a random sample of 49 tyres has a mean life of 15200 km. This sample was drawn from a population whose mean is 15150 kms and a standard ... 2)] Solution : Given n = 49, x = 15200, μ = 15150 and σ = 1200 1 .

Thank you

Answered by tiwariakdi
0

The sample mean is significantly different from the population mean at the 0.05 level of significance.

To test whether the sample mean of 15,200 kms is significantly different from the population mean of 15,150 kms, we can perform a one-sample t-test. The null hypothesis is that the sample is drawn from a population with a mean of 15,150 kms, and the alternative hypothesis is that the sample is drawn from a population with a different mean.

We can begin by calculating the t-statistic:

t = (sample mean - population mean) / (population standard deviation / sqrt(sample size))

t =(15,200 - 15,150) / (1,200 / \sqrt{49} ))

t = 2.17

Using a t-table with 48 degrees of freedom (49 - 1), we find that the critical value for a two-tailed test at the 0.05 level of significance is 2.01. Since our calculated t-value of 2.17 is greater than the critical value, we reject the null hypothesis and conclude that the sample mean is significantly different from the population mean at the 0.05 level of significance.

In other words, we can say that there is sufficient evidence to suggest that the sample of 49 tyres has a different mean life than the population mean of 15,150 kms.

for such more question on standard deviation

https://brainly.in/question/35974439

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