Question

It is common that government revise fares from time to time based on
as inflation and different types of vehicles like auto Rickshaw, Taxi, Radio, Cab etc, the auto
charges in a city comprise of a fixed charge together with the charges for distance covered
study the following situations.
Situation-1 In a city A, for a journey of 10 Km, the charges paid is Rs. 75 and for a journey
of 15 km, the charges paid is Rs.110.
Situation-II in a city B, for a journey of 8 Km, the charges paid is Rs. 91 and for a journey of
14 km, the charges paid is Rs. 145.
Answer the following questions:
Refer situation-1
(a) If the fixed charges of auto rickshaw be Rs x and the running charges be Rs. Y km/hr.
The pair of linear equations representing the situation is :
(1) x +10y=100 (ii) x + 10 y = 75 (iii) 10x+y=110 (iv) 10x+y =75
X+15y = 75
x+15y = 110 15x+y = 75 15x+y = 110
(b) A person travels a distance of 50 km. The amount be has to pay is:
(0) Rs. 155
(ii) Rs. 255
(iii) Rs. 355
(iv) Rs. 455
Refer situation-11
(c) The pair of linear equations representing this situation is:
(1) X +8y=91 (ii) 8x + y = 91 (iii) x+y=91
(iv) 8x+y = 145
x+14 y = 145
14x+y = 145 14x+y = 145
14x+y = 91
(d) What will a person have to pay for travelling a distance of 30 Km?
(i) Rs. 185 (ii) Rs. 289
(iii) Rs. 275
(iv) Rs. 305
(e) What will a person have to pay for travelling a distance of 25 km.
(1) Rs. 160
(ii) Rs. 280
(iii) Rs. 180 (iv) Rs. 260
​

Answer 1

Answer:

a) x+ 10 y = 75

x+ 15y = 110

b)Rs 355

c) x+8y=91

x + 14y= 145

d) Rs 275

e) Rs 180