Question

it is desired to pass 10% current through a galvanometer of 90 ohm,how much shunt resistance is connected​

Answer 1

Answer:

let total current be 100 A

10% of 100 A will pass from galvanometer = 10A

90A current will pass through shunt

As resistance in parallel will have same voltage

so on equating voltage of shut = voltage of galvanometer

Resistance of shunt ×90 =resistance of galvanometer × 10

Rs × 90 = 90 × 10

Rs = 10 ohm

Answer 2

Concept introduction:

Shunt resistance is used to control the current flow in the circuit.

Explanation:

Given that, it is desired to pass $10$% current through a galvanometer of $90$ ohm.

We have to find, shunt resistance.

According to the question,

let total current be $100 A$

$10$% of $100 A$ will pass from galvanometer = $10A$

$90A$ current will pass through shunt

As resistance in parallel will have same voltage

So on equating voltage of shut = voltage of galvanometer

Resistance of shunt × $90$ =resistance of galvanometer × $10$

Rs × $90$ = $90 * 10$

Rs = $10$ ohm

Final Answer:

Shunt resistance is $10 ohm$.

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