Question

it is from mole concept please solve it

Answer 1

HEY FRIEND HERE'S YOUR ANSWER...

a. It is clear from the equation that two moles of  Ca (NO3) produces produce 4 moles of NO2.

So one mole of  Ca (NO3) will give 2 moles of NO2 on decomposition.

b. Molar mass of Ca (NO3) =102.08 g

Number of moles of O2 produces by 65.6 g Ca (NO3) = 65.6/102.08 =  0.6426

At STP volume of 1 mole O2 = 22.4 L

Volume of  0.6426 mole =  0.6426 x 22.4 = 14.4 L

 

C. One mole Ca (NO3) gives one mole CaO

i.e. 

102.08 g Ca (NO3) gives 56.08 g CaO.

65.6 g Ca (NO3) will give (56.08/102.08) x 65.6 g CaO = 36.388 g CaO

 D.  One mole of Ca (NO3) gives 5 mole of gases products i.e. 4 mole OF NO2 and one mole O2

Mass of one mole Ca (NO3) = 40+14+ 3 x 16 = 102.08 g


E. 44.8 L NO2  at STP = 2 mole NO2

Mass of Ca (NO3)  required to produce 44.8 L NO2 at STP = Mass of  1 mole of Ca (NO3) = 102.8 g