It is given that 1 is a zero of the polynomial 7x- x square - 6, find its zeroes.
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Answer:
1 and 6
Step-by-step explanation:
Given that,
There is a quadratic polynomial such that,
7x - x^2 - 6
Also, one of it's zeroes is 1.
To find the other zero.
First of all Let's make it a quadratic equation.
For that, we need to equate this to 0.
Therefore, we will get,
=> 7x - x^2 - 6 = 0
=> -(-7x + x^2 + 6) = 0
=> -7x + x^2 + 6 = 0
=> x^2 - 7x + 6 = 0
Here, we have,
- a = 1
- b = -7
- c = 6
Let the required zero be m.
We know that,
Sum of roots = -b/a
Therefore, we will get,
=> m + 1 = -(-7/1)
=> m + 1 = -(-7)
=> m + 1 = 7
=> m = 7 -1
=> m = 6
Hence, the zereos are 1 and 6.
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