Question

it is given that 3 A + 2 b is equals to 5 c find the value of 27 a cube + 8 b cube minus 125 C cube if ABC is equal to zero​

Answer 1

Step-by-step explanation:

27a³ + 8b³ - 125c³= (3a)³+ (2b)³ + (-5c)³

3a + 2b = 5c

3a + 2b - 5c = 0

Hence, (3a)³ + (2b)^3 + (-5c)³ = 3 (3a) (2b)(-5c)

= -90 abc = -90 x 0 = 0.ans...

Answer 2

The required answer is 0.

Step-by-step explanation:

It is given that

$3A+2B=5C$

It can be written as

$3A+2B-5C=0$

We know that if a+b+c=0, then $a^3+b^3+c^3=3ab$.

In the given problem a=3A, b=2B ,c=-5C and 3A+2B-5C=0.

$(3A)^3+(2B)^3+(-5C)^3=3(3A)(2B)(-5C)$

$27A^3+8B^3-125C^3=-90ABC$

It is given that ABC=0,

$27A^3+8B^3-125C^3=-90(0)$

$27A^3+8B^3-125C^3=0$

Therefore, the required answer is 0.

#Learn more

If a^3+b^3+c^3 = 3abc, and a+b+c = 0, show that (b+c)^2/3bc +(c+a)^2/3ac + (a+b)^2/3ab = 1.

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