Question

it is given that 5 (3/8) × b( 1/2) =19 (where the two fractions are mixed fractions) then find a+b​

Answer 1

$5\frac{3}{a} \times b \frac{1}{2} = 19$

$\frac{5a + 3}{a} \times \frac{2b + 1}{2} = 19$

$\frac{5a(2b + 1) + 3(2b + 1)}{2a} = 19$

$\frac{10ab + 5a + 6b + 3}{1} = 38a$

$10ab + 6b + 3 = 33a$

From this eq. we get,

$a = \frac{10ab + 6b + 3}{33}$

$b = \frac{33a - 10ab - 3}{6}$

using this we get a+b as,

I'm leaving it here I'll reconsider my way and come to it tomorrow please don't report or I'll have to start from nothing...