It is given that 65610 is divisible by 27 which two numbers nearest to 65610 are divisible by 27
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Solution:-
65610 ÷ 27 = 2430
So, the numbers nearest to 65610 and divisible by 27 will be:-
(2430 - 1) × 27 and (2430 + 1) × 27
i.e. 2429 × 27 = 65583
and 2431 × 27 = 65637
(or 65610 - 27 = 65583 and 65610 + 27 = 65637) Answer.
65610 ÷ 27 = 2430
So, the numbers nearest to 65610 and divisible by 27 will be:-
(2430 - 1) × 27 and (2430 + 1) × 27
i.e. 2429 × 27 = 65583
and 2431 × 27 = 65637
(or 65610 - 27 = 65583 and 65610 + 27 = 65637) Answer.
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