it is given that ∆ABC ~∆PQR with BC/QR=1/4. Then ar(∆PRQ)/ar(∆BCA) is equal to
a) 16
b) 3
c) 1/4
d) 1/16
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Solution: Given, triangle ABC ~ triangle PQR. We know that for similar triangles, the ratio of area of triangle is equal to the ratio of square of corresponding sides. Therefore, ar(PRQ)/ar(ACB) = 16.05-Nov-2020
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