Question

It is given that cos 6 = a cos 6 + b Cos 4 + c cos 4 + d cos 3 + e cos 2 + f cos + g. Then the value of (a-c)2 +b2+ d2-(e-g)2-2 f2 is equal to ?​

Answer 1

Answer:

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Answer 2

Answer:

1=RHS

Step-by-step explanation:

sin6θ+cos6θ+3sin2θcos2θ

⇒LHS=(sin2θ)3+(cos2θ)3+3sin2θcos2θ

Using, [a3+b3=(a+b)3−3ab(a+b)]

⇒LHS=(sin2θ+cos2θ)3−3sin2θcos2θ(sin2θ+cos2θ)3+3sin2θcos2θ

⇒LHS=1−3sin2θcos2θ+3sin2θcos2θ=1=RHS