Question

It is given that in a group of 3 students, the probability that the 2 students have the same birthday is 0.008 .what is the probability that the students not having the same birthday

Answer 1

here probability of 2 students not having the same birtyday = 0.008

probability that 2 students have the same birthday =1-p(e)

=1-0.008

=0.992

Answer 2

Answer:

the amount of student the probability = 3

the amount of student that have same birthday = 2

total = 3+2

3

+ your question answer is : 5

2