It is given that in a group of 3 students, the probability that the 2 students have the same birthday is 0.008 .what is the probability that the students not having the same birthday
Answers
Answered by
1
here probability of 2 students not having the same birtyday = 0.008
probability that 2 students have the same birthday =1-p(e)
=1-0.008
=0.992
Answered by
2
Answer:
the amount of student the probability = 3
the amount of student that have same birthday = 2
total = 3+2
3
+ your question answer is : 5
2
Similar questions