Question

It is given that in a group of 3 students the probability of 2 students not having the same birthday is 0.992 what is the probability that the2 students have the same birthday

Answer 1

0.008 is the probability that the 2 students have the same birthday

Answer 2

$heyy mate \\ \\ here \: is \: your \: answer$

let E be the event of having the same birthday

P(E) =0.992

But P(E) +P = 1

P= 1-P(E)

= 1-P(E)

=1-0.992

=0.008